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35+5x-x^2=0
We add all the numbers together, and all the variables
-1x^2+5x+35=0
a = -1; b = 5; c = +35;
Δ = b2-4ac
Δ = 52-4·(-1)·35
Δ = 165
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{165}}{2*-1}=\frac{-5-\sqrt{165}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{165}}{2*-1}=\frac{-5+\sqrt{165}}{-2} $
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